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Different order of XML nodes in a new solution
Sorting XML
If your reference and current XML structures are in a different order you can run below XSLT to sort them before comparision:
| Code Block |
|---|
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="@* | node()">
<xsl:copy>
<xsl:apply-templates select="@* | node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="<PARENT>">
<xsl:copy>
<xsl:apply-templates select="@* | node()[not(self::<CHILD>)]"/>
<xsl:apply-templates select="<CHILD>">
<xsl:sort select="<SORT_BY>" order="ascending"/>
</xsl:apply-templates>
</xsl:copy>
</xsl:template>
</xsl:stylesheet> |
<PARENT> - node name of the parent node of the node to be sorted
<CHILD> - node to be sorted
<SORT_BY> - by which field in <CHILD> it should be sorted